- Masa Atómica.
- Composición Porcentual.
- Formula Empírica.
C9H13NO3
- Masa Atómica:
- C = 9 * 12g = 108g
- H = 13 * 1g = 13g
- N = 1 * 14g = 14g
- O = 3 * 16g = 48g----------------
= 183g
- Composición Porcentual:
- C = 9 * 12g = 108g
- H = 13 * 1g = 13g
- N = 1 * 14g = 14g
- O = 3 * 16g = 48g----------------= 183g
°1 mol ~~~~> C9H13N03 ~~~~> 183g
°183g = 100%
°108g C ~~~~> 100% C9H13NO3
--------------------------------- = 59,016g C%
183g C9H13NO3
°108g C ~~~~> 100% C9H13NO3
--------------------------------- = 59,016g C%
183g C9H13NO3
°13g H ~~~~> 100% C9H13NO3
--------------------------------- = 7,103g H%
183g C9H13NO3
°14g N ~~~~> 100% C9H13NO3
----------------------------- = 7,650g N%
183g C9H13NO3
°48g O ~~~~> 100% C9H13NO3
----------------------------- = 26,229g O%
183g C9H13NO3 ----------------------
= 99,998
--------------------------------- = 7,103g H%
183g C9H13NO3
°14g N ~~~~> 100% C9H13NO3
----------------------------- = 7,650g N%
183g C9H13NO3
°48g O ~~~~> 100% C9H13NO3
----------------------------- = 26,229g O%
183g C9H13NO3 ----------------------
= 99,998
- Formula Empírica:
° C = 59,016% ~~~~> 59,016 C
° H = 7,103% ~~~~> 7,103 H
° N = 7,650% ~~~~> 7,650 N
° O = 26,229% ~~~~> 26,229 O
° 59,016g C ~~~~> 1 mol C
-------------------- = 4,918 mol C
12g C
° 7,103g H ~~~~> 1 mol H
-------------------- = 7,103 mol H
1g H
° 7,650g N ~~~~> 1 mol N
------------------- = 0,546 mol N
14g N
° 26,229g O ~~~~> 1 mol O
------------------- = 1,643 mol O
16g O
° C = 4,918
----------------- = 9
0,546
° H = 7,103
----------------- = 13
0,546
° N = 0,546
----------------- = 0
0,546
° O = 1,643
----------------- = 3
0,546
° Forma ~~~~> C9H13NO3
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